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Q.

The rate of effusion of two gases A & B under identical conditions of T & P are in the ratio of 2 : 1.What is the ratio of RMS velocity of their molecules if TA and TB are in the ratio of 2 : 1

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a

1:2

b

2:1

c

2 : 1

d

22:1

answer is D.

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Detailed Solution

rArB=MBMA=21 & TATB= CACB=TATB×MBMA=21×4122:1
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