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Q.

The rate for a first order reaction is 0.693×10−2 mol L−1min⁡−1 and the initial concentration of the reactants is 1 M, t1/2 is equal to

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a

6.932 min

b

100 min

c

0.6932×10−3min⁡

d

0.6932×10−2min⁡

answer is B.

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Detailed Solution

r=k[reactant]1∴ k=0.693×10−21also t1/2=0.693k=0.6930.693×10−2=100 min⁡
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