The rate law for a chemical reaction is given as Rate=KA2B; When the concentration of A is quadrapled and concentration of B is doubled then rate increases by
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a
16 times
b
64 times
c
32 times
d
8 times
answer is C.
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Detailed Solution
Let Ainitial=Binitial=1M; Initial rate,r1=KA2B; r1=K121; r1=K; Final rate, r2=K422; r2=32K