Q.

The rate law of a reaction A+B→Product is rate =K[A]n[B]m. On doubling the concentration of A and halving the concentration of B, the ratio of new rate to the earlier rate of reaction will be:

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a

n−m

b

2n−m

c

12m+n

d

m+n

answer is B.

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Detailed Solution

r0=K[A]n[B]mr1=K[2A]n[B/2]mr1=K2n−m[A]n[B]mor    r1=r×2n−m
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The rate law of a reaction A+B→Product is rate =K[A]n[B]m. On doubling the concentration of A and halving the concentration of B, the ratio of new rate to the earlier rate of reaction will be: