Q.
The rate law for a reaction between the substances P and Q is given by rate =k[P]a[Q]b. On doubling the concentration of P and reducing the concentration of Q to one-half, the ratio of the new rate to the earlier rate of the reaction will be
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
12(a+b)
b
2(a−b)
c
(a−b)
d
(a+b)
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Rate =k[P]a[Q]b New rate =k[2P]aQ2b=k⋅2a[P]a⋅[Q]b2b =2(a−b)⋅k[P]a[Q]b=2(a−b)⋅ rate ∴ New rate Rate =2(a−b)
Watch 3-min video & get full concept clarity