Q.

The rate law for a reaction between the substances P and Q is given by rate =k[P]a[Q]b. On doubling the concentration of P and reducing the concentration of Q to one-half, the ratio of the new rate to the earlier rate of the reaction will be

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

12(a+b)

b

2(a−b)

c

(a−b)

d

(a+b)

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Rate =k[P]a[Q]b New rate =k[2P]aQ2b=k⋅2a[P]a⋅[Q]b2b                 =2(a−b)⋅k[P]a[Q]b=2(a−b)⋅ rate ∴        New rate  Rate =2(a−b)
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon