Q.
The rate law for a reaction between the substances P and Q is given by rate =k[P]a[Q]b. On doubling the concentration of P and reducing the concentration of Q to one-half, the ratio of the new rate to the earlier rate of the reaction will be
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a
12(a+b)
b
2(a−b)
c
(a−b)
d
(a+b)
answer is B.
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Detailed Solution
Rate =k[P]a[Q]b New rate =k[2P]aQ2b=k⋅2a[P]a⋅[Q]b2b =2(a−b)⋅k[P]a[Q]b=2(a−b)⋅ rate ∴ New rate Rate =2(a−b)
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