The rate law for a reaction between the substances P and Q is given by rate =k[P]a[Q]b. On doubling the concentration of P and reducing the concentration of Q to one-half, the ratio of the new rate to the earlier rate of the reaction will be

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12(a+b)

2(a−b)

(a−b)

(a+b)

answer is B.

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Detailed Solution

Rate =k[P]a[Q]b New rate =k[2P]aQ2b=k⋅2a[P]a⋅[Q]b2b =2(a−b)⋅k[P]a[Q]b=2(a−b)⋅ rate ∴ New rate Rate =2(a−b)

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