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Q.

The rate law for the reaction RCl+NaOH(aq)→ROH+NaCl is given by Rate = k[RCl]. The rate of the reaction will be

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a

unaffected by increasing temperature of the reaction

b

doubled on doubling the concentration of NaOH

c

halved on reducing the concentration of NaOH to one half

d

halved on reducing the concentration of RCI to half

answer is D.

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Detailed Solution

R1=k[RC]1[NaOH]0R2=k[0.5 RCl]1∴ R2=0.5 R1
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