Q.

The rate of radioactive decay of a sample are 3 × 108 dps and 3 ×107 dps after time 20 min and 43.03 min respectively. The fraction of radio atom decaying per second is equal to

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a

1600

b

1

c

0.5

d

0.001

answer is A.

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Detailed Solution

k=2.303t2−t1log⁡r1r2=2.30323.03log⁡3×1083×107=0.1min−1k=−dN/Ndt=0.1min−1=1600s−1
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