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Kinetics of chemical reactions

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By Expert Faculty of Sri Chaitanya
Question

The rate of a reaction triple when temperature changes from 20°C to 50°C. Calculate energy of activation for the reaction. (R=8.314JK1mol1)

Moderate
Solution

The Arrhenius equation is,

log10k2k1=EaR×2.303T2T1T1T2

 Given: k2k1=3;R=8.314JK-1 mol-1;T1=20+273=293 K

and T2=50+273=323K

Substituting the given values in the Arrhenius equation,

log103=Ea8.314×2.303323293323×293

Ea=2.303×8.314×323×293×0.47730=28811.8Jmol1

Ea=28.81kJmol1


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