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Q.

The ratio of activities of two radio nuclides X and Y in a mixture at time t=0 was found to be 4 : 1. After two hours, the ratio of activities become 1:1. If the t½ of  radio nuclide X is 20 min, then t½, [in minutes] of radio nuclide Y is:

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a

10

b

20

c

30

d

40

answer is C.

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Detailed Solution

A0(X)A0(Y)=41;AxAy=1Ky−Kx=1tln⁡A0yA0x×AxAyKy−Kxt=ln⁡14;t1/2y=30min
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