Ratio of Cp and Cv of a gas 'X' is 1.4. The number of atoms of the gas 'X' present in 11.2 litres of it at N.T.P. is

Since  CpCu=1.4. the gas should be diatomic.If volume is 11.2 It then, no. of moles =12∴ no. of molecules =12× Avogadro's NO.no. of atoms =2×no. of molecules2×12× Avogadro's No.=6.023×1023