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Q.

The ratio of the energy of the electron in ground state of hydrogen to the electron in first excited state of Be3+  is

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a

1 : 4

b

1 : 8

c

1 : 16

d

16 : 1

answer is A.

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Detailed Solution

En=−13.6 Z2n2eV,  whereZ=atomic  number =4N=number  of  orbitsBe3+  n=2  first  excited  stateE1=−13.6  eV,  E2=−13.6  ×  16/4E1:E2=4:16 =1:4
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The ratio of the energy of the electron in ground state of hydrogen to the electron in first excited state of Be3+  is