The ratio of FeC2O4 (ferrous oxalate) and ferric oxalate used per mole of Cr2O72- in acidic medium is _________.
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answer is 2:1.
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Detailed Solution
FeC2O4 is oxidised to Fe3+ and Cr2O72− to 2Cr3+Fe2+→Fe3++e−CrO42−→2CO2+2e−n=36e−+Cr2O72−→2Cr3+(n=6) In Fe2C2O43,Fe3+ is not oxidised, but 3C2O42− is oxidised to 6CO2⋅( So n=6) FeC2O4≡Cr2O72− Fe2C2O43≡Cr2O72−1Eq≡1Eq 1Eq≡1Eq13mol≡16mol 13mol≡16mol1mol of Cr2O72− 1mol of Cr2O72−=63=2mol of FeC2O4 =1mol of Fe2C2O43 Ratio of mol of FeC2O4 and Fe2C2O43=21=2:1