First slide

Classification of organic compounds

Question

Ratio of hybrid orbitals to pure ‘p’ orbitals in Ethene molecule is

Moderate

A

3 : 1
B

1 : 1
C

3 : 2
D

2 : 3

Solution

$H_{2} \overset{{sp}^{2}}{C} = \overset{{sp}^{2}}{C} H_{2}$
Each ‘sp²’ carbon contains 3 'sp²' hybrid orbitals and 1 pure ‘p’ orbital ;
H-atom utilizes its pure ‘s’ orbitals in bonding.
Number of 'sp²' hybrid orbitals = 2 $\times$ 3 = 6
Number of pure ‘p’ orbitals = 2 $\times$ 1 = 2
Number of pure ‘s’ orbitals = 4 $\times$ 1 = 4
Ratio of hybrid orbitals to pure ‘p’ orbitals = 6 : 2 = 3 : 1 ;

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