The ratio of magnetic moments of Fe (III) and Co (II) is:

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5:7

35:15

7 : 3

24:15

answer is B.

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Detailed Solution

Fe( III )−[Ar]3d5; unpaired electrons =5 Magnetic moment =5(5+2) BM Co(II) −[ Ar ]3d7; unpaired electrons =3 Magnetic moment =3×(3+2) BM

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