Ratio of number of hybrid orbitals to pure orbitals ‘p’ in ethyne molecule is

Number of ‘sp’ orbitals = 2 x 2 = 4Number of ‘p’ orbitals = 2 x 2 = 4Number of ‘s’ orbitals = 2 x 1 = 2Ratio of hybrid orbitals to pure ‘p’ orbitals = 4 : 4Ratio of hybrid orbitals to pure ‘p’ orbitals = 1 : 1