Questions
The ratio of sp, sp2 and sp3 orbitals in the product ‘B’ formed from the reaction below
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a
2:3:4
b
1:3:4
c
2:3:10
d
4:3:9
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Correct option is A
[Step 1]: terminal alkyne on reaction with sodamide forms sodium acetylide, [Step 2]: Sodium acetylide on reaction with methyl halide forms compound B. The steps are respectivelyCompound ‘B’ is having 2 sp carbons, 2 sp2 carbons and 2 sp3 carbons Total sp orbitals are 2*2=4, total sp2 orbitals are 2*3=6 and total sp3 orbitals are 2*4=8 Therefore the ratio is 2:3:4Similar Questions
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