The ratio of the value of any colligative property for K4[Fe(CN)6] solution to that of Fe4[Fe(CN)6]3 (prussian blue), solution is nearly

van't Hoff factor (i) for K4[Fe(CN)6] is 5 (assuming complete ionization) K4[Fe(CN)6]      →↓1 molecule 4K+↓4 cations+[Fe(CN)6]−4↓1 anionSimilarly, i for Fe4[Fe(CN)6]3 is 7 As we know, colligative properties ∝iiK4[Fe(CN)6]iFe4[Fe(CN)6]3=Colligative properties of K4[Fe(CN)6]Colligative properties of Fe4[Fe(CN)6]3=57=0.71