Q.

The ratio of the value of any colligative property for K4[Fe(CN)6] solution to that of Fe4[Fe(CN)6]3 (prussian blue), solution is nearly

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

0.71

1.4

Less than 1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

van't Hoff factor (i) for K4[Fe(CN)6] is 5 (assuming complete ionization) K4[Fe(CN)6] →↓1 molecule 4K+↓4 cations+[Fe(CN)6]−4↓1 anionSimilarly, i for Fe4[Fe(CN)6]3 is 7 As we know, colligative properties ∝iiK4[Fe(CN)6]iFe4[Fe(CN)6]3=Colligative properties of K4[Fe(CN)6]Colligative properties of Fe4[Fe(CN)6]3=57=0.71

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET