Ratio of wavelengths of first line in Lyman series of hydrogen atom to second line in Balmer series of hydrogen atom is
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a
1 : 16
b
1 : 8
c
1 : 4
d
1 : 2
answer is C.
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Detailed Solution
For Lyman series, n1= 1;For first line of Lyman series n2= 1+1= 2 ;For Balmer series, n1= 2;For second line of Balmer series n2= 2+2= 4 ;For H-atom, Z=1;ν-=1λ=RHZ21n12-1n22 ; ν1-ν2-=112-122122-142 =34×163=4 ; λ1λ2=14;