For the reaction : aA → bB, it is given that log⁡[−dAdt]=log⁡[dBdt]+0.6020. What is a : b is?

aA→bB−1a(dAdt)=1b(dBdt) or −dAdt=ab×dBdtlog⁡(−dAdt)=log⁡(ab)+log⁡(dBdt)Given : log⁡(−dAdt)=log⁡(dBdt)+0.6020∴ log⁡(ab)=0.6020=2×0.3010=2×log⁡2=log⁡4∴ a:b=4