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In the reaction,
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a
6 L HCI (aq) is consumed for every 3L H2(g) produced
b
33.6 LH2(g) is produced regardless of temperature and pressure for every mole Al that reacts
c
67.2 LH2(g) at STP is produced for every mole Al that reacts
d
11.2 LH2(g) at STP is produced for every mole HCl(aq) consumed
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Correct option is D
2Al(s)+6HCl(aq)⟶2Al3+(aq)+6Cl-(aq)+3H2(g)3×22.4 LH2(g) at STP is produced by 6 moles of HCl(aq) Hence, 11.2 LH2( g ) at STP is produced by 1 mole of HCl(aq) consumed.Talk to our academic expert!
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