Q.

In the reaction. 2Al(s)+6HCl(s)→2Al(aq) 3++6Cl(aq) −+3H2(g)

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a

6 lit HCl(aq)   is consumed for every  3 lit H2(g)

b

33.6lit H2(aq) is produced regardless of temperatureand pressure for every mole Al that reacts

c

67.2 lit H2(g) at STP  is produced for every mole Al that reacts

d

11.2 lit H2(aq)   is produced for every mole  HCl(aq)  consumed

answer is D.

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Detailed Solution

2Al(s)+6HCl(aq)⟶2Al3+(aq)+6Cl−(aq)+3H2(g)For each mole of HCl  reacted, 0.5 mole of  H2  gas is formed at STP. 1 mole of an ideal gas occupies 22.4 lit at STP. Volume of  H2  gas formed at STP per mole of HClreacted is  22.4×0.5   litre.
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In the reaction. 2Al(s)+6HCl(s)→2Al(aq) 3++6Cl(aq) −+3H2(g)