For the reaction A + 2B ⇌ 2C at equilibrium [C] = 1.4 M, AO = 1 M, BO = 2 M, CO = 3 M. The value of KC is
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a
0.084
b
8.4
c
84
d
840
answer is A.
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Detailed Solution
Since C0 = 3 M, at eq. it is 1.4 M. So reaction must go in backward direction A + 2B ⇌ 2C Initial conc. 1 2 3Eq. conc. 1 + x/2 2 + x 3 - xGiven 3 - x = 1.4 M ⇒ x = 1.6 MKC = C2A B2=1.421.83.62, putting values KC = 0.084