The reaction A→B follows first order kinetics. The time taken for $$0.8$$ mole of A to produce $$0.6$$ mole of B is $$1$$ hour. What is the time taken for conversion of $$0.9$$ mole of A to produce $$0.675$$ mole of B?

Question

The  reaction A→B     follows first order kinetics. The time taken for $$0.8$$  mole of A to produce $$0.6$$ mole of B is $$1$$ hour. What is the time taken for  conversion of $$0.9$$ mole of A to produce $$0.675$$ mole of B?

Infinity Learn · Accepted Answer

A      →                      B $$t=$$      $$0$$                                            $$0.8$$                               $$0t=$$      $$1$$                                             (0.8$$−$$0.6)                $$0.6t=$$      $$0$$                                             $$0.9$$                               $$0t=$$      ?                                              (0.9$$−$$0.675)              $$0.6751st$$ order, $$t=2.303klogaa$$−$$x1=2.303klog0.80.2$$                          $$k=2.3031log$$ $$4k=2.303$$  ×  $$0.6020t=2.3032.303$$×$$0.6020log0.90.225=2.303$$×$$0.60202.303$$×$$0.6020=1$$  hr.

The reaction A→B follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B?

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