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Q.

A reaction 2A+B→kC+D is first order with respect to A and 2nd order with respect to B. Initial conc. (t = 0) of A is C0 while B is 2C0. If at t as 30 minutes the conc. of C is C0/4, then rate expression at t = 30 minutes is:

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a

R=7 C03 k/16

b

R=27 C03 k/32

c

R=247 C03 k/64

d

R=49 C03 k/32

answer is D.

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Detailed Solution

2A+B→kC+Dr=K[A]1[B]2 r0=K(C0)1(2C0)2=4K(C0)3...(1) 2A+B→kC+Dt=0       C0 2C0 0 0 (C0−2x) (2C0−x) x x If x=(C04) then  [A]=C0−C02=C02                             [B]=2C0−C04=7C04r=KC027C042=49K(C0)332
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