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For the reaction, A+BProducts,  the rate law is given as rate=KAB . When the concentration of A is doubled and the concentration of B made one fourth then rate

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a
becomes half
b
Increases by eight times
c
Increases by two times
d
remains unaffected

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detailed solution

Correct option is A

Let initial concentration of  A=B=1M ∴rinitial=K11=K;rfinal=K214 rfinal=12 K;

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