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For the reaction, A+BProducts,  the rate law is given as rate=KAB2. When the concentration of A is doubled and the concentration of B is halved then rate

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a
remains unaffected
b
becomes half
c
Increases by sixteen times
d
Increases by two times

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detailed solution

Correct option is B

Let initial concentration of  A=B=1M ∴rinitial=K112=K;rfinal=K2122rfinal=12 K;

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