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Q.

For the reaction A+2B→products (started with concentrations taken in stoichiometric proportion), the experimentally determined rate law is: −d[A]dt=k[A][B]The half life time of the reaction would be:

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a

0.693k

b

0.6931/k

c

0.6932k

d

not defined

answer is C.

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Detailed Solution

A+2B→productsa−x 2a−2x  −d[A]dt=k[A][B]Reactant are in their stoichiometric proportion ⇒−d(a−x)dt=k(a−x)2(a−x)dxdt=2k(a−x);       t1/2=0.6932k
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