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Q.

For a reaction to be spontaneous at all temperatures

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a

∆G  and ∆H should be negative

b

∆G for the reaction is zero

c

∆G  and ∆H should be positive

d

∆H < ∆G

answer is A.

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Detailed Solution

∆G  = ∆H-T∆SFor spontaneous reaction at all temperature∆H=-ve∆S=+veSo ∆G  =-ve∆G  = ∆H-T∆SFor spontaneous reaction at all temperature∆H=-ve∆S=+veSo ∆G  =-ve
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