For a reaction to be spontaneous at all temperatures
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a
∆G and ∆H should be negative
b
∆G for the reaction is zero
c
∆G and ∆H should be positive
d
∆H < ∆G
answer is A.
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Detailed Solution
∆G = ∆H-T∆SFor spontaneous reaction at all temperature∆H=-ve∆S=+veSo ∆G =-ve∆G = ∆H-T∆SFor spontaneous reaction at all temperature∆H=-ve∆S=+veSo ∆G =-ve