The reaction between H2O2 and KMnO4 is2KMnO4+3H2SO4+5H2O2→ K2SO4+2MnSO4+8H2O+5O2In a reaction excess of H2O2is added to 0.1 mole of acidified KMnO4solution. Then the S.T.P volume of O2 liberated is
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a
5.6 lit
b
6.6 lit
c
11.2 lit
d
22.4 lit
answer is A.
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Detailed Solution
for 2 mole of KMnO4 - - - - - 5×22.4 lit of O20.1 mole of KMnO40.1×5×22.42=5.6lit