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Hydrogen Peroxide

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By Expert Faculty of Sri Chaitanya

Question

The reaction between H₂O₂ and KMnO₄ is 2KMnO₄+ 3H₂SO₄ + 5H₂O₂ → K₂SO₄ + 2MnSO₄ + 8H₂O + 5O₂.If 30 ml H₂O₂ is required to reduce 15 ml 0.02 M KMnO₄ solution, the molarity of H₂O₂ is

Moderate

Solution

2 KMnO₄ + 3H₂SO₄ + 5H₂O₂ → K₂SO₄ + 2MnSO₄ + 8H₂O+5O₂
No of equivalents of H₂O₂ = No of equivalents of KMnO₄

$\large [N_1V_1]_{H_2O_2}\;\;=\;\;[N_2V_2]_{KMnO_4}$

N₁ x 30 = 0.02 x 5 x 15

$\large \\\therefore\;\;N\;=\;\frac{No\;of\;equivalents}{V(in\:lit)}\\\\\because\;N\;=\;M\times n-Factor\\\\=\;0.02\times 5$

$\large \\\\N_1\;=\;\frac{0.02\times 5\times 15}{30}\\\\N_1\;=\;0.01\times 5\\\\N_1\;=\;0.05N\\\\M_{H_2O_2}\;=\;\frac{N_1}{N-factor}\;=\;\frac{N_1}{Basicity}\\\\M_{H_2O_2}\;=\;\frac{0.05}{2}\;=\;0.025M$

$\large \therefore$
0.025M,30ml H₂O₂ is required to reduce 15ml of 0.02M KMnO₄ solution.

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