For the reaction, 5Br−+BrO3−+6H+⟶3Br2+3H2OIf −dBr−dt=k1Br−,−dBrO3−dt=k2Br− dBr2dt=k3Br− then k1,k2 and k3are related as

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k1=5k2=1.66k3

3k1=k2=5k3

5k1=3k2=k3

k1=k2=k3

answer is A.

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Detailed Solution

For the reaction, 5Br−+BrO3−+6H+⟶3Br2+3H2O −15dBr−dt=−dBrO3−dt=13dBr2dt 15k1Br−=k2Br−=13k3Br−or 3k1=15k2=5k3 k1=5k2=1.66k3

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