In the reaction, Br2+2NaOH→NaBr+NaOBr+H2O , the oxidant and reductant respectively are
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a
Br2, NaOH
b
Br2, Br2
c
NaOH, Br2
d
NaOH, NaOH
answer is B.
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Detailed Solution
This is a disproportionation reaction. Bromine undergoes both oxidation and reduction.1) Br2→Br-...reduction 0 -1 .......decrease in ox. state; 2) Br2→BrO-.....oxidation 0 +1.......increase in ox. state