Q.

In the reaction, Br2+2NaOH→NaBr+NaOBr+H2O ,  the oxidant and reductant respectively are

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a

Br2, NaOH

b

Br2, Br2

c

NaOH, Br2

d

NaOH, NaOH

answer is B.

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Detailed Solution

This is a disproportionation reaction. Bromine undergoes both oxidation and reduction.1) Br2→Br-...reduction        0     -1 .......decrease in ox. state; 2) Br2→BrO-.....oxidation       0      +1.......increase in ox. state
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In the reaction, Br2+2NaOH→NaBr+NaOBr+H2O ,  the oxidant and reductant respectively are