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For a reaction at 25°C enthalpy change (∆H) and entropy change (∆S) are −11.7×103Jmol−1 and −105Jmol−1K−1 respectively. Find out change in gibbs free energy whether this reaction is spontaneous or not?

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answer is 19.59 AND NONSPONTANOUS.

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Detailed Solution

Given, ΔH=−11.7×103Jmol−1 ΔS=−105Jmol−1K−1T=298K ∴ΔG=ΔH−TΔS=−11700−298×(−105)=19590J= +19.59 kJSince ∆G: +ve .'. reaction is not spontaneous.

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