Q.

For the reaction C2H6→C2H4+H2 the reaction enthalpy ΔlH= kJmol−1 (Round off to the Nearest Integer) [Given : Bond enthalpies in KJmol−1:C−C=347,C=C=611C−H=414,H−H=436]

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 128.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Δ,H=ϵC−C+2ϵC−H−ϵC−C+ϵH−H=[347+2×414]−[611+436]=128

Watch 3-min video & get full concept clarity

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!

For the reaction C2H6→C2H4+H2 the reaction enthalpy ΔlH= kJmol−1 (Round off to the Nearest Integer) [Given : Bond enthalpies in KJmol−1:C−C=347,C=C=611C−H=414,H−H=436]