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Q.

For the reaction C2H6→C2H4+H2 the reaction enthalpy ΔlH= kJmol−1 (Round off to the Nearest Integer) [Given : Bond enthalpies in KJmol−1:C−C=347,C=C=611C−H=414,H−H=436]

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answer is 128.

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Detailed Solution

Δ,H=ϵC−C+2ϵC−H−ϵC−C+ϵH−H=[347+2×414]−[611+436]=128
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