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Q.

For the reaction C2H6→C2H4+H2The reaction enthalpy ΔrH=______________kJ mol−1.(Round off to Nearest Integer]. [Given : Bond enthalpies in kJ mol−1.:C−C:347,C=C:611;C−H:414,H−H:436]

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answer is 128.

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Detailed Solution

ΔH=∑(BE)R−∑(BE)P=[C−C+6C−H]−[C=C+4C−H+H−H]=[347+6(414)]−[611+4+(414)+436]=128

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