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In the reaction, CaCO3s⇌CaOs+CO2g, 50 grams of CaCO3 is allowed to dissociate in 22.4 lit vessel at 8190c. If 50% of CaCO3 is left at equilibrium, active masses of CaCO3,CaO and CO2 at equilibrium respectively are

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answer is 2.

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Detailed Solution

Given T = (819 + 273) K50% of calcium carbonate dissociated at equilibrium At equilibrium, solid=CaCO3=CaO=1;At equilibrium, nCO2=0.25, Vvessel=22.4 lit ;

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