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Q.

For the reaction:CO(g)+12O2(g)→CO2(g)ΔH∘=−67650cal at 25∘CCalculate ∆H at 100°C, given that the required molar heat capacities are as follows:CP(CO, gas )=6.97cal/∘CCPCO2, gas =8.47cal/∘CCPO2,gas=7.00cal/∘C

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a

-54.6 cal

b

-676s0.4 cal

c

-67684.4 cal

d

-67762.5 cal

answer is D.

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Detailed Solution

ΔH100∘−=ΔH25∘C∘=Cp2−Cp2ΔT⇒ ΔH100∘=758.97−6.97−72+ΔH25∘C∘= (- 112.50 - 67650) cal = - 67762.5 cal.
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