Reaction Emf Gibbs free energy
$H_{2} + {Cl}_{2} \to 2 HCl$ $E_{1}$ ${ΔG}_{1}$
$\frac{1}{2} H_{2} + \frac{1}{2} {Cl}_{2} \to HCl$ $E_{2}$ ${ΔG}_{2}$
Correct relation is

Moderate

Solution

Cell potential and electro potentials are intensive properties …. uninfluenced by stoichiometry where as Gibbs free energy is an extensive property.
$∴ E_{1} = E_{2} & {ΔG}_{1} = 2 {ΔG}_{2}$

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