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Q.

In a reaction at equilibrium 'X' mole of the reactant A decompose to give 1 mole each of C and D. If the fraction of A decomposed at equilibrium is independent of initial concentration of A, then the value of 'X' is:

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answer is 2.

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Detailed Solution

XA⇌Ca00a(1−α)aαXaαXK=[C][D][A]X=a2α2X2V2a(1−α)VX=α2⋅a2−XX2(1−α)X⋅V2−X If α is independent of a, then 2−X=0 or X=2.
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