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Q.

In a reaction at equilibrium ‘X’ moles of the reactant A decomposes to give 1 mole each of C and D. If the fraction of A decomposed at equilibrium is independent of initial concentration of A then the value ‘X’ is

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a

1

b

3

c

2

d

4

answer is B.

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Detailed Solution

xA ⇌ C + D a 0 0 at initiala(1 - a) aαx aαx at equilibriumK=C DAx = α2 a2x2v2a 1-αVx =α2a2-αx21-αxV2-x∵ α is independent of A ⇒ 2-x=0 or x=2

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