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Q.

For the reaction F2(g)+2HCl(g)→2HF(g)+Cl2(g) ΔH∘ at 298K is −84.4kcal,ΔHf∘(HF)=−64.2kcal/molΔHf∘ for the HCl(g) per gram is

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a

-0.603 kcal

b

-0.603 cal

c

0.0603 kcal

d

6.03 kcal

answer is B.

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Detailed Solution

F2(g)+2HCl(g)→2HF(g)+Cl2(g)ΔH=−84.4=−128.4−2ΔHf(HCl)ΔHf(HCl)=−22kcal/molΔHf(HCl)=−0.603kcal/g

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