In the reaction, F2 + 2NaOH →2NaF + OF2 + H2O, which undergoes oxidation?
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a
F
b
O
c
H
d
Na
answer is B.
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Detailed Solution
F20+2Na+1O-2H+1→2Na+1F-1+O+2F-12+H+12O-2F2 undergoes reduction(0 to -1)F2 is the Oxidising agentNaOH undergoes Oxidation (Ox. state of Oxygen changes from -2 to +2)NaOH is the reducing agentElements undergoing Oxidation is Oxygen