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$For the reaction {Fe}_{2} N (s) + \frac{3}{2} H_{2} (g) ⇌ 2 Fe (s) + {NH}_{3} (g)$

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Kc=KpRT32

Kc=KpRT

Kc=KpRT−12

Kc=KpRT12

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detailed solution

Correct option is D

Fe2Ns+32H2g→2Fes+NH3gΔng=no. of moles of gaseous products - no. of moles of gaseous reactants=1−32 =−12 Kp=Kc(RT)Δng⇒Kp=Kc(RT)−1/2⇒Kc=Kp(RT)1/2

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For the reaction Fe2N(s)+32H2(g)⇌2Fe(s)+NH3(g)

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$For the reaction {Fe}_{2} N (s) + \frac{3}{2} H_{2} (g) ⇌ 2 Fe (s) + {NH}_{3} (g)$