Q.

For the reactionA2(g)  +  2B2    ⇌    2C2(g)the partial pressure of A2 and B2 at equilibrium are 0.80 atm and 0.40 atm respectively. The pressure of the system is 2.80 atm. The equilibrium constant Kp will be

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a

20

b

5.0

c

0.02

d

0.2

answer is A.

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Detailed Solution

A2(g)  +  2B2    ⇌    2C2(g)PA2 = 0.80  atmPB2 = 0.4  atmTotal pressure of the system = 2.8 atm∴   PC2  =  2.8 - 0.8 - 0.4 = 1.6Kp = PC22PA2  ×  PB23  =  1.620.8 ×  0.42 = 20
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