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Q.

For the reactionAg+2Bg → 2Cg+3Dg,The value of ∆H  at 270C  is  19.0 kcal. The value of ∆E for the reaction would beR=2.0 cal K-1 mol-1

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a

20.8 kcal

b

19.8 kcal

c

18.8 kcal

d

17.8 kcal

answer is D.

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Detailed Solution

∆H=∆E + ∆ngRT 19=∆E + 2 × 2 × 3001000kcal 19=∆E +1.2 ∆E =19-1.2 kcal=17.8 kcal
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