The reaction A(g)+2B(g)→C(g)+D(g) is an elementary process. In an experiment involving this reaction, the initial partial pressures of A and B are pA=0.60 atm and pB=0.80 atm respectively. When pc=0.20 atm , the rate of the reaction relative to the initial rate is
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a
16
b
112
c
136
d
118
answer is A.
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Detailed Solution
A(g)+2B(g)→C(g)+D(g) Rate=k[PA] [PB]2=k(0.60)(0.80)2 ……………………..(i)When pc=0.20 atm pA is reduced to 0.40 and pB=0.40(See stoichiometric representation)Rate =k[0.40][0.40]2 ……………………………..(ii)∴ II divide by II=0.40×0.40×0.400.60×0.80×0.80=16