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Q.

The reaction A(g)+2B(g)→C(g)+D(g) is an elementary process. In an experiment involving this reaction, the initial partial pressures of A and B are pA=0.60 atm and pB=0.80 atm respectively. When pc=0.20  atm , the rate of the reaction relative to the initial rate is

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a

16

b

112

c

136

d

118

answer is A.

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Detailed Solution

A(g)+2B(g)→C(g)+D(g) Rate=k[PA]  [PB]2=k(0.60)(0.80)2 ……………………..(i)When pc=0.20  atm  pA  is  reduced  to  0.40  and  pB=0.40(See stoichiometric representation)Rate =k[0.40][0.40]2 ……………………………..(ii)∴  II divide by II=0.40×0.40×0.400.60×0.80×0.80=16
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