In the reaction given below,B← $$H2$$−$$Pd/BaSO4CH3$$−C≡C−$$CH3$$→$$AlcoholNa/NH3A$$ A and B are

Correct option is 4A is trans-2-Butene and B is cis -2- Butene

Questions

In the reaction given below,
$B \leftarrow_{}^{H_{2} - P d / B a S O_{4}} C H_{3} - C \equiv C - C H_{3} \to_{A l c o h o l}^{N a / N H_{3}} A$ A and B are

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Cis-2-butene in both cases

Trans-2-butene in both cases

A is cis-2-Butene and B is trans-2-Butene

A is trans-2-Butene and B is cis -2- Butene

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detailed solution

Correct option is D

Addition of hydrogen in the presence of Lindlar catalyst give cis, due to the fact that the intermediate is transition state and attack of both hydrogen atom from same side. In Birch reduction the Option-II the intermediate is dianion.

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In the reaction given below,B← H2−Pd/BaSO4CH3−C≡C−CH3→AlcoholNa/NH3A A and B are

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Ready to Test Your Skills?

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In the reaction given below,
$B \leftarrow_{}^{H_{2} - P d / B a S O_{4}} C H_{3} - C \equiv C - C H_{3} \to_{A l c o h o l}^{N a / N H_{3}} A$ A and B are