First slide

Alkynes

Question

In the reaction given below,
$B \leftarrow_{}^{H_{2} - P d / B a S O_{4}} C H_{3} - C \equiv C - C H_{3} \to_{A l c o h o l}^{N a / N H_{3}} A$ A and B are

Moderate

A

Cis-2-butene in both cases
B

Trans-2-butene in both cases
C

A is cis-2-Butene and B is trans-2-Butene
D

A is trans-2-Butene and B is cis -2- Butene

Solution

Addition of hydrogen in the presence of Lindlar catalyst give cis, due to the fact that the intermediate is transition state and attack of both hydrogen atom from same side. In Birch reduction the Option-II the intermediate is dianion.

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