Q.

For the reaction. H2 + I2 ⇌ 2 HI, K = 47.6. If the intial number of moles of each reactant  and product is 1mole then at equilibrium

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a

I2=H2,I2>[HI]

b

I2=H2,I2<[HI]

c

I2

d

I2>H2,I2=[HI]

answer is B.

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Detailed Solution

Following is the given equilibrium.47.6=(1+2x)2(1-x)(1-x)=[HI]2H2×I2The numerator has to larger than the denominator.More product is formed .At equillibrium H2=I2<[HI]
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