For the reaction. H2 + I2 ⇌ 2 HI, K = 47.6. If the intial number of moles of each reactant and product is 1mole then at equilibrium
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a
I2=H2,I2>[HI]
b
I2=H2,I2<[HI]
c
I2
d
I2>H2,I2=[HI]
answer is B.
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Detailed Solution
Following is the given equilibrium.47.6=(1+2x)2(1-x)(1-x)=[HI]2H2×I2The numerator has to larger than the denominator.More product is formed .At equillibrium H2=I2<[HI]