The reaction of ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3{\mathrm{Cl}}_3\left(\mathrm{A}\right)$ with ${\mathrm{LiBH}}_4$ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3{\left(\mathrm{Me}\right)}_3.$Compounds (B) and (C) respectively are:

• A

  Borazine and MeMgBr

• B

  Boron nitride and MeBr

• C

  Borazine and MeBr

• D

  Diborane and MeMgBr