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Q.

A reaction has ∆H=-33 kJ  and ∆S=-58JK. This reaction would be

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a

spontaneous at all temperatures

b

non-spontaneous at all temperatures

c

spontaneous above a certain temperature

d

spontaneous below a certain temperature

answer is D.

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Detailed Solution

∆G= ∆H↓-Ve-T∆S↓-VeSince both are -ve, the reaction would have a -ve ∆G below a temperature3300058 K=569 K.
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